Thread: bash: if santax help: [ X ] && [ Y ] || [ Z ]

how write in sh/bash

javascript/php:

code:

if ( 1 == 1 && ( 1==2 || 2==2 ) ) {  }

this closest can without breaking it:

code:

if [ 1 -eq 1 ] && [ 1 -eq 2 ] || [ 2 -eq 2 ];then  fi

edit: forget it, it's wrong. following posts explain why.. trying variations, may post corrected 1 later..

code:

if [[ 1 -eq 1 && 1 -eq 2 || 2 -eq 2 ]];then  fi

works me.

example :

code:

a=2; b=3; c=4; if [[ $a -eq 2 && $b -eq 2 || $c -eq 4 ]]; echo yes; fi

..change declared values or test values , see difference. works -
if (condition 1) , (condition2 or condition3), then go ahead..

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